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3.(15 PTS) A textbook of physical chemistry proposes that spʻ hybrid orbitals(corresponding to the geometry shown in the figu
Combining all this reasoning leaves the hybrid orbitals as: 60 4o=41 42ptapos the = ca Pzp. Jag 925-60 $2pe 4c=c4P2p - 5 $25
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Answer #1

we know » Emn = 1; if m=n = 0.34 min. and Emn = 4 m/ VnY; Im and Un are To normalized wave fn. i fore Vasil, and he T40 1 4

PO and h4 a 16) = 0 L4 a 14 c) = 0 also <^P0/%) =0 From TV a 14a) = 1 X 4 Popz 11 23 02s a Pepe - 1/2 2 2 2 2 7 = 1 2 <Q 2pz

using Taal &by=0. → K7 Popx - 320 C4 topx - 1 / 3 / 25 to Popn) = 0 - D 4 tapz|9app) - Jasa Popz Ifa) - 1 ts pz 18 px - 1 2 3

ata = / P2pz - 13 925. 4 - topz - 42-vz popu Me = -1/2 Papx - 1 / 2 1 2 4 + 1/ 2 Capa. bu Fore Va to be normalized; tra&ay =

Fooi 4 and to to be outhogonal; T461407 = 0. LHS. ektep 2 - - eg & - xdog en fly er og r - (ve|eby * * * <*dep|*tby (94-) = f

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