Question

#7. A vessel whose walls are thermally insulated contains 2.70 kg of water and 0.460 kg of ice, all at a temperature of 0.0 °C. The outlet of a tube leading from a boiler in which water is boiling at atmospheric pressure is inserted into the water. How many grams of steam must condense inside the vessel (also at atmospheric pressure) to raise the temperature of the system to 27.0 °C? Neglect the heat transferred to the container.

Answer 1

- 80 kcal by or latent heat of vapowization = Lu= 540 Kalkg latent heat of fusion 4- al/kg specific heat of water = c = 1 Kcal/kg °C Heat recieved water tice Qr = (mucot), +(m; 4f + m; (AT) + [2-70x1x1} (27-o)]+[(0,4680x13) + 0.4621 310'4(27-0)) cal 1.22 x 105 cal of &lost = Heat lost by vapour = (mL + MCAT) Q,= (mx 540xle%) +[ mx IX 10?x (60-27)] cal (613x10²m) cal for no heat lost to surrounding Or = Q 1.22X105 = 613x10m kg = lag gram Hence, mass of vapour/steam condensed = 199 gram let m = mass - vapour condensed ma 1-22X105 0.199 613X103 kg