1. (10 points) For the following questions, let p, q, r e Z be distinct positive...

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Answer 1

Answer #1

To solve this problem we make use of "combinations of primes" possible to form a factor of given number.

This is also a generalized formula known as "Tau (n)" i.e. number of positive divisors of a given number "n".

Given: m=p²q²r i Piq, r = distinct primes (i.) Then number of positive divisors of in = T(m) = (2+1) (2+1) (1+1) = (18 posit

Answer 2

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