When an acid loses a proton, it forms its conjugate base as-
HA (acid) -------------> H+ + A- (conjugate base)
Now if we say a conjugate base is more stable, that means its acid must have lost the proton very easily and fast to produce a stable compound. So we can say stable conjugate bases are formed from stronger acid which loses proton very easily.
Again in organic compounds, generally we will find a negative charge as base. So here we also have to see that the formed negative charge is more stable on the atom or not. If it is present on its stable position, then the conjugate base is more stable.
So the general rule is- Negative charges are more stable on electronegative atoms than on other atoms-
Now from the given structures-
Rank the stability of the following conjugate bases from MOST to LEAST stable (Most = 1,...
2. Carbocation stability: Rank the following carbocations from the most stable to the least stable. + (a) (b) (c) (d)
Rank the following carbocations in order of decreasing stability. Most Stable Least Stable Least Stable
Rank the following carbocations in order of decreasing stability. Most Stable Least Stable Least Stable
2. Rank the following radicals in decreasing order of stability (1-most stable, 5-least stable): CH2 CH3 (CH3)2Ć (CH3)2CH CH3CH2
Part A Arrange the complexes in order of decreasing stability. Rank from most stable to least stable. To rank items as equivalent, overlap them. View Available Hint(s) Reset Help NiF 2 Cu(en),]2 Cu(NH)2 Co(en)(H2O)2 Most stable Least stable
Rank the following carbocations in order of decreasing stability Most Stable Least Stable og ở bu
Rank the following carbocations in order of increasing
stability. “1” is the least stable, “4” is the most stable
or ot an CH3 or
Rank the following carbocations in increasing order of
stability. (1 = least stable)
3. (5 points) Rank the following carbocations in increasing order of stability. (1 = least stable) eg og Å
Rank the following radicals in order of decreasing stability (most stable to least stable 11 III TV III > I > I > IV III > | > | > IV Ill > IV> || >1 IV>]> || > III II >> III > IV
1. Rank the following carbocations in order of increasing stability. "I" is the least stable, "4" is the most stable. (2 pts) or and an ove сна