Question

JK Flip-Flop S R Flip-Flop From(Q) To (Q+) S 0 0 R T Flip-Flop From(Q) To(Q+) 0 0 JK From(Q 0 To (Q+) 0 -- - c) Complete the timing diagram below. Assume that both of flip-flops are edge triggered. (10 pts) Clock

please show all work

Answer 1

The Activation Table for the SR flip flop is

Q Q+ S R

0 0 0 X Possible inputs are S = 0,R = 1 and S = 0,R = 0 therefore R can (0 or 1) ie X

0 1 1 0

1 0 0 1

1 1 X 0

X -> Dont care it can be either 0 or 1.

The Activation Table for the T flip flop is

Q Q+ T

0 0 0 When T is 1 it toggles other wise it remains in the same state.

0 1 1

1 0 1   

1 1 0   

The Activation Table for the J K flip flop is

Q Q+ J K

0 0 0 X  

0 1 1 X   

1 0 X 1

1 1 X 0   

Here in the circuit diagram the JK flip flop is acting as a T flip flop because botht the J and K are connected to a single input and it is Negative Edge triggered,

And the second flip flop is acting as a Positive Edge triggered flipflop.That means its state changes only during the positive edge transition.

Timing Diagram

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Here as you can see that the dotted line indicates the transition phase of the change of state of the flip flop,Which is either the positive edge in the case of the D flip flop and negative edge of the clock in the case of the JK flip flop.