Question

Design of Machine Elements (Spring 2019) Name: 1. Known: A gear exepts the same known force on each of two geometrically different steel shafts supported by self- aligning bearings at A and B. Find: Draw shear and bending moment diagrams for each shaft. Schematic and Given Data: 100 N 100 N +200- 300 +200- 300— 140 50 N 2. Known: A know maximum normal stress is produced by a bending moment. Find: Determine the value of bending moment • In a straight round rod of 40 mm diameter • In a straight square rod, 40 mm on a side 40 mm 40 mm max = 400 MPa 3. Determine the vertical and horizontal displacement of point A on the angle bracket due to the concentrated force P. The bracket is fixed connected to its support. El is constant. Consider only the effect of bending.

Answer 1

Solution to question 1:

1OON 05 а A I 200mm 200mg 300mm Consider moment about A EMA=0 - (100) (200) + RB (200 +300) = 0 . RB = 20000 = 40N 500 PA+ Rp-100=0 PP + 40-60 = 0 :-RAGON Shear force at various points ! VA - = 60 SFD and BMD: V = 60-100 =-40N 100N B = 60-100+40=0 & c AR200 Ane 1200 300- Bending moment at various points DOON MA=0 MB=0 Mc = Rp x 300 = 40x300 -40N = 12000 N.mm 12,000 N.mm BMD

B D 2200 300 RB ON 16) Consider moment about Ai loon SMA=0 - 100 (200) + R2 (500) + solfo)-o - RB = 24 N EFy=0 Rot Re-100+50=0 RA - 24 - (02+ b = 0 | ZA -4L | hear force at various points VA = Rp = 74N V = RA-100 = 74-100 = -26N B = – 26 + R₂ = -26-24 = CSON D = -50+50=0 SED & BMD: 10ON SON Bending moment at various points! MA=0 Mb=0 Mc = PAX 200 = +44 (200) Mc=14800 Nomm -26 VAM -SO SED 14800 N.mm MB - 50x140= 7000 N.mm Ovo Niram BMD