Question

Design a complete mechanical power transmission for a conveyor system. There are 28 – 40 lbs boxes on the conveyor at 1 time, the construction is rubber on wood at a 0^o angle from the horizontal, the diameter of the conveyor pulley is 6”, the velocity of the belt is 270-280 ft/min. Assume heavy shocks and 10+ hours per day operation.

Answer 1

We should be design system for maximum values of all parameters weight w = 40 lbs Angle of inclination alpha = 0 degree velocity v = 280 ft/min Tension in vert is calculated from following relation T_b = 1.37 times f times L times g times [2m_i + (2 m_b + m_m) cos alpha] m_i = idler weight /ft = 5 lb/m [say] m_bt = belt weight/foot = 1/2 lb/m [say] m_m = weight of converted material /ft = w f = coefficient of friction = 0.2 ft/s^2 length of belt l = 560 f so L = l/2 = 560/2 = 280 ft t_b = 1.37 times 0.2 times 280 times/6 times 0.305/0.0254 = 1120.7 rad/min hence required power p = tau w/60 p = 4368.165 times 1120.7/60 watt p = 81590.0 watts = 81.59 kw