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Formulas for Questions 24-27 Upper control in. UCL= 1 + 20 Lower control it. LCL - P - 20% where p mean traction detective in
size of each sample Table 2. A manufacturer of precision machine parts produces a specialty bracket. They inspected random sa
XCIO Question 24 Using Table 2. determine the upper and lower p-chart control is the number of standard deviations is 0.19 0.
Question 26 Using Table 2, the standard deviation of the sampling distribution is 0.0715 0.0560 0.0492 0.0933 0.0335 Question
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Answer #1

Question 24)

p-bar = Total number of defective/(no of samples*sample size) = 54/(9*70) = 0.085714286

Sp = sqrt((0.085714286*(1-0.085714286))/70) = 0.033459431

UCL = 0.085714286+3*0.033459431 = 0.186092579 = 0.19 (approximately)

LCL = 0.085714286+3*0.033459431 = -0.014664007 = 0 (Adjusted)

So correct answer is 0.19,0

Question 25)

Graph Data

Sample no Number defective Fraction defective center line LCL UCL
1 4 0.057 0.0857143 0 0.186093
2 5 0.071 0.0857143 0 0.186093
3 0 0 0.0857143 0 0.186093
4 7 0.1 0.0857143 0 0.186093
5 14 0.2 0.0857143 0 0.186093
6 2 0.029 0.0857143 0 0.186093
7 1 0.014 0.0857143 0 0.186093
8 7 0.1 0.0857143 0 0.186093
9 14 0.2 0.0857143 0 0.186093

p-chart 1 2 3 4 5 6 9 7 LCL 8 UCL - Fraction defective center line -

Correct answer is The percentage defective is out of control

Question 26)

The standard deviation of the sampling distribution is 0.033459431 = 0.0335 (approximately) (Ans)


Question 27)

Correct answer is At least one sample is outside the control limits

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