Question

A 0.01 mL spherical air bubble is injected into a polycarbonate cylindrical tube approximately 1.8 m in height and 0.125 m in diameter. The tube is filled up with water. The air bubble rises slowly in water due to the buoyancy force. The drag and gravity forces are also acting on bubble when it rises. After some intervals, bubble achieves the terminal velocity (U,) at steady state conditions where all forces are balanced. The drag force of the water on bubble is given by FD,, where u is the viscosity of water and D, is the volume equivalent bubble diameter. Calculate the volume equivalent bubble diameter in m, the bubble terminal velocity in m/sec and the buovancy force that acts on a bubble in N. The same size of a bubble is injected again into the same cylindrical tube that is full of a new liquid. This new liquid is prepared by mixing xanthan gum by weight of 0.05% concentration with water. Do you think the buoyancy force that acts on the bubble is now reduced or increased? Explain your answer. Assuming the following data below for your calculation and neglecting the bubble weight, (i) The viscosity of water: 1.0×103 Pa.s @20C. (ii) The viscosity of xanthan gum solution: 0.03024 Pa.s @ 20 C. (ii)The density of water: 998.3 kg /m@20 C. (iv)The density of air: 204 kg/m@20 C. (V) The density of xanthan gum solution: 990 kg /m@ 20 C. (20 Marks)

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-C 3. Draa force 2. y = 0.2645 m/s

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