n = 8
dof = n - 1 = 7
t (alpha/2) = 1.415
from t table
Use Table F to find the ta/2 value for a 90% confidence interval for the mean...
Question 3 of 5 (1 point) Use Table F to find the ta/2 value for a 90% confidence interval for the mean when the sample size is 8. 1a/2 -
Find the t critical value ta/2 to calculate a 95% confidence interval for a population mean when the sample size is 17. and the real value tar to kolesa 250w contence mentor a population meanwhen the samples Find the t critical value ta/2 to calculate a 9096 confidence interval for a population mean when the sample size is 25. 23
We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find ta/2, df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.) ta/2,df a. b. 2.228 A 90% confidence level and a sample of 11 observations. A 95% confidence level and a sample of 11 observations....
What is the t-value for a 90% confidence interval for the mean if the sample size is 24? a. 1.984 b. 1.714 c. 2.069 d. 1.96 e. 2.306 In general, when choosing the sample size for estimating a mean, which of the following will result in a smaller margin of error (E)? a. a larger confidence level b. a smaller sample size c. a dozen glazed donuts d. a larger sample size e. a more expensive calculator
Find the critical value tą to be used for a confidence interval for the mean of the population in each of the following situations. (a) a 95% confidence interval based on n = 18 observations (b) a 90% confidence interval from an SRS of 28 observations (c) an 80% confidence interval from a sample of size 80
Use the margin of error of 4, confidence interval of 90% and ?=28 to find the minimum sample size required to estimate an unknown population mean ?.
Suppose the 90% confidence interval for the mean SAT scores of applicants at a business college is given by [1,694, 1,836]. This confidence interval uses the sample mean and the sample standard deviation based on 25 observations. [You may find it useful to reference the t table.] What are the sample mean and the sample standard deviation used when computing the interval? (Round "t" value to 3 decimal places and “Sample mean” and "Sample standard deviation" to 2 decimal places.)
Assuming that the population is normally distributed, construct a 90% confidence interval for the population mean, based on the following sample size of n-6. 1, 2, 3, 4, 5, and 19 Change the number 19 to 6 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval. Find a 90% confidence interval for the population mean, using the formula or calculator. [ ] SHS (Round to two...
Answers only is fine! Find the critical value zc necessary to form a confidence interval at the level of confidence shown below. c=0.92 Find the margin of error for the given values of c, σ, and n. c = 0.95, σ =2.4, n = 8.1 Level of Confidence. zc 90% 1.645 95% 1.96 99% 2.575 Construct the confidence interval for the population mean μ. c=0.98, x=9.5, σ=0.3, and n= 52 Construct the confidence interval for the population mean μ. c=0.95, x=16.7, σ=6.0, and n=...
A 90 % confidence interval (a t interval) for the mean lives (in minutes) of Kodak AA batteries is ( 440, 480 ). Assume that this result is based on a sample of size 15 . 1) What is the value of the sample standard deviation? a) 43.9784 b) 57.7796 c) 57.5895 d) 44.1856 2) Construct the 99% confidence interval. a) (426.1974,493.8026) b) (430.1984,489.8016) c) (443.2129,476.7871) d) (444.7772,475.2228) 3) If the confidence interval (442.7050 ,477.2950) is obtained from the same...