Suppose the 90% confidence interval for the mean SAT scores of
applicants at a business college is given by [1,694, 1,836]. This
confidence interval uses the sample mean and the sample standard
deviation based on 25 observations. [You may find it useful
to reference the t table.]
What are the sample mean and the sample standard deviation used
when computing the interval? (Round "t" value to 3
decimal places and “Sample mean” and "Sample standard deviation" to
2 decimal places.)
Suppose the 90% confidence interval for the mean SAT scores of applicants at a business college...
The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's male and female applicants. A random sample of 12 male applicants results in a SAT scoring mean of 1053 with a standard deviation of 30. A random sample of 18 female applicants results in a SAT scoring mean of 1155 with a standard deviation of 42. Using this data, find the 90% confidence interval for the true mean difference between the...
The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 8 in-state applicants results in a SAT scoring mean of 1106 with a standard deviation of 57. A random sample of 18 out-of-state applicants results in a SAT scoring mean of 1073 with a standard deviation of 47. Using this data, find the 90% confidence interval for the true mean difference between the...
The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's in-state and out-of-state applicants. A random sample of 19 in-state applicants results in a SAT scoring mean of 1228 with a standard deviation of 39. A random sample of 11 out-of-state applicants results in a SAT scoring mean of 1168 with a standard deviation of 31. Using this data, find the 80% confidence interval for the true mean difference between the...
The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT) for the school's male and female applicants. A random sample of 15 male applicants results in a SAT scoring mean of 1151 with a standard deviation of 37. A random sample of 6 female applicants results in a SAT scoring mean of 1095 with a standard deviation of 38. Using this data, find the 95% confidence interval for the true mean difference between the...
Long Answer Questions 3. A random sample of Math SAT Scores of 20 applicants to the Isenberg School of Management are reported with a mean of 510 and a variance of 930. Assume that the Math SAT scores for Isenberg applicants are normally distributed - a) Construct a 90% confidence interval for the sample. b) Interpret your answer to part a. Put your answer to part a into context of the actual question c) If we changed it to a...
We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find tα/2,df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.) a. A 90% confidence level and a sample of 13 observations. b. A 95% confidence level and a sample of 13 observations. c. A 90%...
We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find tα/2,df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.) tα/2,df a. A 90% confidence level and a sample of 25 observations. b. A 95% confidence level and a sample of 25 observations. c. A...
We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find ta/2, df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.) ta/2,df a. b. 2.228 A 90% confidence level and a sample of 11 observations. A 95% confidence level and a sample of 11 observations....
We use the t distribution to construct a confidence interval for the population mean when the underlying population standard deviation is not known. Under the assumption that the population is normally distributed, find tα/2,df for the following scenarios. (You may find it useful to reference the t table. Round your answers to 3 decimal places.) tα/2,df a. A 90% confidence level and a sample of 25 observations. b. A 95% confidence level and a sample of 25 observations.
2) (3 points) A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medical study is (2020, 2160). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 20 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use...