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6.2.31-T Question Help Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of O and a standard deviation of 1. Find the probability that a given score is between -2.07 and 3.92 and draw a sketch of the region. Sketch the region. Choose the correct graph below. ОА. Ов. Q Q A 207392 2.07 3.92 -2.07 3.92 -2.07 3.92 The probability is (Round to four decimal places as needed.) Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of O and a standard deviation of 1. Draw a graph and find P13, the 13th percentile. This is the bone density score separating the bottom 13% from the top 87% Which graph represents P13? Choose the correct graph below. ОВ. Oc OD Q A P13 P3 P13 Pa The bone density score corresponding to P3 is - (Round to two decimal places as needed.) Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of O and a standard deviation of 1. Find the probability that a given score is less than -1.63 and draw a sketch of the region. Sketch the region. Choose the correct graph below. OA B. Oc Л -1.63 1.63 -1.63 1.63 -1.63 The probability is (Round to four decimal places as needed.)

Answer 1

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Here z values probability calculate from standard normal distribution table.

ACTO: 1 1 page soluton :- assuming that a randomly selected subject is given a bone density test. Those test scores are normally distributed with mean o' and standard deviation of i @ we want to find probability that a given score is between -2.02.and je P(-2.07 < x < 3.92) xe bone density P (-2.07. 4 26 (40 P(-2.07 <<<3.92) PC?<3.92) - PC-2007) PCZ73.92) - (1-P (Z< 2007) 1- (- 0.9808) 8.92-4 0.9808 PC-2.07 < *43.92) = 0.9808 Sketch of the region: D). 0.9808 -2.07 3.92 b Now, we want to find 18th percentile le. p(x+x) = 0.13 P(x4 (9-4) Plax 20) To [P(32%) =0.13 ] -0.13 -0.13

page from standard normal distribution table P (2 <.1. 12) = 0.13 from egn o & ear ② jie P13 = 2.12 sketch of 13th percentile A). o P13=-1-12 @ Now We have to find probability that given score is less than 1063. PCX <- 63) Plyw -1.63-44 2 11 Pla <-) 63) - 1- P(X<1.63) = -0.9484, [P(x<=1163) = 0.0516] Sketch of the region. D). 0.0516 -1.63