The test scores is normally distribution with a mean 0 and a standard deviation is 1.
We have to find the probability of a bone density test score greater than 0.29.
Greater than means right side area therefore correct option is D.
Now we have to find a P(Z > 0.29)
P(Z > 0.29) = 1 - P(Z < 0.29) = 1 - 0.6141 = 0.3859
The probability is 0.3859
Question Help Assume that a randomly selected subject is given a bone density test. Those test...
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