Question

1-cell with following properties (under 1-Sun Area :30 cm2 ; lsc-1A; Voe* 0.6Y; FF 8096 Fig. 1: Solar module with 4x 10 solar cells. Cells in each row are connected in series and the 4 rows are connected in parallel. fthe solar module in Fig. I is

Answer 1

Here Cells in each raw are connected in series. In a series connection, current will be same and voltage will be added up. Similarly, 10 Cells in each raw are connected in series, their short circuit current remains same and open circuit voltage will be added. Then 4 raw are connected in parallel. In parallel connection, current will be added up and voltage remains same. Thus,

a)

Short Circuit current of solar module = $4\times I_{sc} = 4\times 1 = 4A$

b)

Open circuit voltage of solar module = $10\times V_{oc}$ = $10\times 0.6 = 6V$

c)

Efficiency of each solar cell,   $\eta =\frac{P_{max}}{EA}$

where E : Solar Irradiance

A : Area of cell

Fill Factor, $FF = \frac{P_{max}}{V_{oc}I_{sc}}$

Thus, $\eta =\frac{P_{max}}{EA}=\frac{FF\times V_{oc}I_{sc}}{EA}$

  $=\frac{FF\times V_{oc}I_{sc}}{EA} = \frac{0.80\times 0.6\times 1}{1000\times 50\times 10^{-4}} = 0.096=9.6\%$

d)

Efficiency of solar module

  $=\frac{FF\times V_{oc}I_{sc}}{EA} = \frac{0.80\times 6\times 4}{1000\times 50\times 10^{-4}\times 40} = 0.096=9.6\%$

e)

Thickness needed for anti-reflection coating,  $d=\frac{\lambda }{4r}$

where, $\lambda$ : Wavelength

r : Refractive index

Thus, thickness = $\frac{600}{4\times 2.5} =60nm$