Assume that in (Figure 1) I = 11 A and d = 60 cm .
What is the magnitude of the force on the first wire?
wires carrying current in same direction attaract each other and wires carrying current in opposite direction repel each other.
r2 = distance between wire 1 and 2 = 2 cm = 0.02 m
r3 = distance between wire 1 and 3 = 2 + 2 cm = 0.04 m
F2 = force on wire 1 by wire 2 = (/4) (2i2d/r2) = (10-7) (2 (11)2(0.60)/0.02) = 7.26 x 10-4 N
F3 = force on wire 1 by wire 3 = (/4) (2i2d/r3) = (10-7) (2 (11)2(0.60)/0.04) = 3.63 x 10-4 N
Net force on wire 1 is given as
Fnet = F2 - F3 = (7.26 x 10-4 ) - (3.63 x 10-4 ) = 3.63 x 10-4 N
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