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Course Home <Chapter 23 Homework Problem 23.43 - Enhanced - with Feedback 12 of 13 > Review | Constants A 15 F capacitor init
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Answer #1

SOLUTION :

equation for charge during discharging is

Q = Qo e^-t/RC

e^-t/RC = Q/Qo = 10uC/30uC

e^-t/RC = 0.34

-t/RC = ln (0.34)

-t/RC = -1.098

t = 1.098 * RC

t = 1.098 * 1500 * 15 *10^-6

t = 0.0245 Secs

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