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Let De be the dihedral group of order 12. In other words, Do = {e,r,r2, m3, 74, 75, s, rs, rs, rºs, r*s, r® s} where p6 = 92
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solution De= şe,r, 82, 83, 84, 85, 8,788, 822, 23, 24, 2532 where ro= 8²=e & sr=rts. @ H = {1,.3, so, 3823 is not a subgroup16. K={1,8, 83, r3s} is a subgroup of Do. because K is finite and also k is closed under Иe Swiskөч 9 ) , С ісц -I- - Bir?.-732

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