3. In an experiment, 2.50 grams of CoCl26H2O is heated until all of the water is...

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Answer 1

Answer #1

3. a) Assuming a molecule of CoCl₂.6H₂O : Mass of the molecule = 58.9 + 2 * 35.5 + 6 * 18 = 237.9

Mass of Water = 6 * 18 = 108

Mass fraction of water in the compound = 108 / 237.9 = 0.454

Grams of watre removed from the sample = mass of sample * mass fraction of water = 2.5 * 0.454 = 1.135 g

b. Grams of CoCl₂ = mass of sample - mass of water = 2.5 - 1.135 = 1.365 g

Answer 2

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