Question

19 110 a 3 68. 3 bla 168a. a 39. C 3구 19a. 5 110.2 2135.구 aa4. 14.12 643.04 9ㅋ54.46 3552-28 i119.66 3 68.3 귀구. 구8 구68.43 2135

Solve the matrix by Gauss-Jordan elimination method. Show ALL steps with formulas.
Ans:
X1= 3.122
X2= 0.644
X3= -0.009
X4= 0.504
X5= -0.119
X6= -2.465
X7= 1.505

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Answer #1

Given, 19 110.2 368.3 612 1682.2 39.6 37 192.5 110.2 642.04 2135.7 3552.28 9754.46 229.52 214.12 1119.66 368.3 2135.7 7155.4519 0 0 0 0 0 0 110.2 368.3 612 1682.2 39.6 37| 192.5 2 .88 -0.44 2.68 -2.3 -0.16 -0.48 3.16 -0.44 16.24526 0.063158 35.3810519 0 0 0 110.2 368.3 612 1682.2 39.6 37| 192.5 2 .88 -0.44 2.68 -2.3 -0.16 -0.48 3.16 0 16.17804 0.472602 35.02966 0.790819 0R5=R5--28.5304/42.5502) *R4 R6=R6-(0.008945/42.5502)*R4 R7=R7-(-0.61715/42.5502)*R4 19 0 0 2 110.2 368.3 612 1682.2 39.6 37|R6=R8(1556944/2895091)*R5 R7=R7-(3.626828/2895091)*R5 .19 _0 110.2 _368.3 _62_1682.2 _39.6 _37|_192.5_ _2.88 -044 _268 -23 -0Now, 0.346248*X7=0.521251 Thus, X7=1.50542 Also, 0.127861*X6+0.059099*X7=-0.22578 Thus, X6=-2.4616 Also 288.6228*X5+1.465249*Also 16.31249*X3 +0.472602*X4 +35.73244*X5 +0.839708*X6 +0.637544*X7=-5.31775 Thus, X3=-0.009 = -0.01 Also, 2.88*X2 +0.44*X3+Hence, X1 = 3.022 X2 = 0.647 X3 = -0.009 0.505 X5 = -0.119 X6 = -2.4616 X7 = 1.50542

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