Provide the molecular formula and the structure given the molecular weight, IR, proton NMR andcarbon NMR.
From molecular wegith: 115 g/gmol
calculate the grams of each :
C% = 62.6% = 115*0.626 = 72g
H% = 11.4% = 13.11 g
N% = 12.3% = 115*.123 = 14.2 g
Now change that to moles!
MWC = 12 g/gmol
MWH = 1 g/gmol
MWN = 14 g/gmol
moles of C = mass / MWC= 72/12 = 6 moles of C
moles of H = mass / MWH =13.11/1 = 13 moles of H
moles of N = mass /MWN = 14.2/14 = 1 mol of N
Compound Formula
C6H13N
this one is probably an amine
CH3-CH2-CH-CH-CH2-CH2-NH2
There is a double bond... we need to use NRM image to find out WHERE it is
From the diagram, there is a C3 peak
CH3-CH2-CH-CH-CH2-CH2-NH2 is correct
Provide the molecular formula and the structure given the molecular weight, IR, proton NMR andcarbon NMR....
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