Homework Answers
here,
QUES 004 ::
displacement = 1.74 m
net force, f = 398 m
work done = force * displacement * CosA
work done = 398 * 1.74 * Cos0
work done = 692.52 J
QUES 005 :
Force, f = 74.9 N
Extension, x = 14.5 cm = 0.145 m
From hooke's law ::
spring force = spring constant * extension
spring constant = spring force / extension
spring constant = 74.9 / 0.145
spring constant = 516.552 N/m
QUES 006 :
work done = 0.5 * k * x ^2
work done = 0.5 * 516.552 * 0.145^2
work done = 5.43 J
Add Answer to:
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refer to picture.
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Caloulate the work required to stretch the following springs 1.5 m from their equilibrium positions. Assume Hooke's law is obeyed a. A spring that required 80 J of work to be stretched 0.2 m from its equilibrium position. b.A spring that required a force of 250 N to be stretched 0.4 m from its equibrium position a. Set up the integral that gives the work done in strotching the spring 1.5 m from its equilibrium position. Use increasing Imits of...
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refer to picture.
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