Given:
Sample size for Whiting, n1 =24
Sample size for Franklin, n2 =21
Mean age in Whiting = =62.9
Std.deviation in Whiting =S1 =5.4
Mean age in Franklin = =58.1
Std.deviation in Franklin =S2 =3.9
Welch's t-test or unequal variances t-test:
Null Hypothesis (H0):
Alternative Hypothesis (H1): (right tailed test)
(where =Population mean age in Whiting and =Population mean age in Franklin).
Test statistic, t= = =3.447
v1=n1-1 =23 and v2 =n2-2 =20
Degrees of freedom, V = = =42
From Student's T distribution table, at V =42 and for right tailed test, tcritical =1.682
Conclusion: t > tcritical (3.447 > 1.682). There is a sufficient evidence to reject the null hypothesis at 0.05 significance level. Hence, there is a statistically significant evidence to claim that the mean age of houses in Whiting is greater than the mean age of houses in Franklin ().
Thus, it can be concluded that the houses in Whiting are older.
Whiting, Indiana, leads the "Top 100 Cities with the Oldest Houses" list with the average age...