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Graph the parabola. y=x²- 10x+27 To graph the parabola, plot the vertex and four additional points, two on each side of the v
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Answer #1

y=x^2-10x+27

To find the vertex of the parabola,put

\frac{\mathrm{d} y}{\mathrm{d} x}=0

2x-10=0

x=5

put x=0 we get y=27

put x=1 we get y=18

put x=6 we get y=3

put x=7 we get y=6

(0,27)and (1,18) are two points on one side of the vertex while

(6,3)and (7,6) are two more points on other side of the vertex

Now we can easily plot the curve

30 (0, 27) 25 20 (1, 18) 15 10- (7, 6) 5- (6, 3) (5, 2) 14 16 12 10 2 4

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