6. Given the following data: Brig) 2 Brig) ΔΗ'-192.5 kJ/mol H2(g) + Br2(g)-) 2HBr(g) ΔΜ"--72.4 k/mol...
Enter your answer in the provided box. You are given the following data: H2(g) → 2H(g) Br2(g) → 2Br(g) AH = 436.4 kJ/mol AH = 192.5 kJ/mol H2(g) + Br2(g) → 2HBr(g) AH = -72.4 kJ/mol Calculate Ahº for the reaction H(g) + Br(g) — HBr(g) kJ/mol
You are provided the following data: H2(g) → 2 H(g) Br(g) → 2 Br(g) H2(g) + Brz(g) → 2 HBr(g) AH = 436.4 kJ/mol AH = 192.5 kJ/mol AH = - 72.4 kJ/mol Calculate AH for the reaction H(g) + Br(g) → HBr(g) Show your work | What is ΔΗ?
Consider the reaction: 2HBR(g) >H2(g) + Br2() Using standard thermodynamic data at 298K, calculate the free energy change when 1.51 moles of HBr(g) react at standard conditions AG° kJ rxn AHof (kJ/mol) AG°F (kJ/mol) s° (J/mol K) Beryllium Вe(s) 0 9.5 -569.0 ВeO(s) -599.0 14.0 Be(ОН)2(s) -902.5 -815.0 51.9 AH°f (kJ/mol) AG°f (kJ/mol) s° (J/mol K) Bromine Br(g) 111.9 175.0 82.4 Br2() 152.2 0 0 Br2(g) 30.9 3.1 245.5 Br2(aq) -3.0 4.0 130.0 -121.0 -175.0 82.0 Br (aq) BrF3(g) -255.6...
35) Given the equilibrium reaction at constant pressure: 2HBr(g) + 72.7 kJ = H2(g) + Br2(g) When the temperature is increased, the equilibrium will shift to the A) left, and the concentration of HBr(g) will decrease B) right, and the concentration of HBr(g) will decrease C) right, and the concentration of HBr(g) will increase D) left, and the concentration of HBr(g) will increase
Please write clearly and use sig figs. thanks in advance 8. A typical candy bar has 35.0 g of glucose. The human body generates energy from glucose by the thermochemical equation provided below C6H1206(S) + 6 O2(g) → 6 CO2(g) + 6 H2O(1) AH=-670 kcal How much energy is obtained from the digestion of a typical candy bar? Show your work Final Answer You are provided the following data: H2(g) → 2 H(g) Br(g) → 2 Br(g) H2(g) + Br2(g)...
For the reaction H2(g) + Br2(g) → 2HBr(g) Kp = 3.6 x 104 at 1494 K. What is the value of Kp for the following reaction at 1494 K? 42 H2(g) + / Br2(g) HBr(g) K". p Submit
5. For the overall exothermic reaction: H2(g) + Br2(g) → 2HBr(g) the following mechanism was determined: fast Equilibrium Step 1: Brz(8) 2Br(g) Step 2: H2(g) + Br(g)_52HBr(g) + H(g) Step 3: H(g) + Br(g) k3 HBr(g) slow fast Use a plot of AH versus Reaction Pathway to illustrate the three step reaction profile.
3. (6 points) Consider the reaction: H2 (g) + Br2 (g) = 2HBr (g), where AH = -103.8 kJ/mol. For a reaction of equal moles of H2 (g) and Br2 (g) at 1.0 atm in a 1.0 L flask at 25 °C, Keq = 2.0 x 10''. a. Calculate the value of AG at 25 °C. b. Calculate the ASº for the reaction. c. Calculate the AS for the surroundings.
A Reaction is given: ½Br2(l) --> Br(g) Ho = 112kJ/mol The bond enthalpy of Br-Br is 193 kJ/mol A. Formulate the vaporization process of 1 mol bromine Br2(l). B. Calculate the enthalpy of the vaporization process bromine. Show calculations C. Calculate the energy invested \ emitted by the evaporation of 3.2 gr of bromine. Show calculations. (Explain how you determined whether the energy is invested or emitted in this process). D.A Reaction is given: ½H2(g) + ½Br2(l) --> HBr(g) Ho...
For the reaction 2HBr(g) H2(g) +. Br2(1) H' = 72.6 kJ and Δ So=-114.5 J/K The equilibrium constant for this reaction at 295.0 K is Assume that Δ11° and Δ Sa are independent of temperature. Submit Answer more group attempt ramaining