(4 points) The RS-232 port on a PC transmits data at 38.4 kbps using polar NRZ...

Question

Question

(4 points) The RS-232 port on a PC transmits data at 38.4 kbps using polar NRZ line code. What is the null to null bandwidth

Answer 1

Answer #1

SOLUTION:-

$\rightarrow$ Null to null bandwidth = + RHZ

= bit rate

= 38.4 KHZ

$\rightarrow$ The PSD of NRZ polar line coding with equally likely bits is given by

$S(f)=V^{2}T\left [ \frac{sin \Pi FT}{\Pi FT} \right ]^{2}$

When the probability of 1 is P, and O is not 0.5, a dc component exists and the PSD becomes

$S(f)= 4V^{2}TP(1-P) \left [ \frac{Sin \Pi FT}{\Pi FT} \right ]^{2}+V^{2}(1-2P)^{2}\delta(F)$

Note:- +1 $\rightarrow$ +V volts }

0 $\rightarrow$ -V volts } representation for NRZ

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Answer 2