Question

Weyheit & Figure 2: Loading Case 1

Answer 1

Solution CASE ca - 30 To 1-. ze T1 C B 2 AC 3 191 N Joint :- * 259 mm * 259 mm * 259 mnt Efy=0 - Fy. Sin 30=0 => Fu -o --zero force member Efx=0 > F3 + fu cos30 =0 => Fz = 0 --- zero force member Joint © :- Efx =0 = FR.COS 30º = Fu cos 30° => FD=0 -- zero force member {fyzo > Is É Fg Gin 30 - Fy sinsu F5 n => F5 =0 ---zero force mentes Joint © :- Elyzo => F6 sinugo + F5 + 191=0 => FG = -253.077 N yhu =0 FG 5 A F2 = 763 119In {fx=0 7 F2 =-Fo cos 49" tf3 => FZ = 166 N to Joint ® :- Efx = 0 F8=0 > F10 Cos 30 = Fq (0530 +Focus ago => F10 = - 191.72 N » fy. Fro sin 30° Fr sinugo => FZ = 95.14 N. Efy=0

Joint B Ery=o → lg sin60+17 = 0 - Tg = - 109.86 N Elz=0 > F = F2 -- Fg Cos 60° => fy 220.93 N. A B 2 Reaction Joint @ HA calculation: - Eryco => Az = 0; Erc=0 → 141 = => HL= 220.93 N F1 - PR - Joint 6 :- Efy = 0 → Re = - Fg sin 60 - foolingo pa = Ro = 191 N. Efx zo > H₂ =- Fg 80560 - fio Cosso H2 = 220.93 N Member I measured force (N) Calculated force (N) error 2010 Col. ☺ co? . Col@-cl 226 N 220.93 5.07 171 N IGON 5 N ON % erres cols lccolo/a/27 xlot 2.9 4 % 1 2.92 % ON ON ON -250N 3.077. ON -253,077 95.140 ON 1.23% 3.90*1. 7 v ggn -4 N -- 113N -203N 3.86N -An -30140 - 109.86 N 2.78 % -191:72 N. 5.56%

CASE @ NA V 49° N 30 B in 1 2 a 3 D 4 170N K 250 mm x 250 mm.sk 250 mmy zo o Joint & Efy = 0 => Fy Sin 30º = 170 7 Fu = 340 N Efreze => F3 = -Fy Cos 30 B = –294.45 N 170N UN - 30 ks Joint ®:- Efx = 0 30 ffy = → » => F8 C0530 = Fu cos 300 F8 = 340 N F5 = F8 Sin 30° - FM Sin 30' F5 =0 --- zero force member Efyzo I joint © - Efyzo » Fo sinugo + F5 =0 . => FG = 0 --- zero force member 7 z =-Fo cos ugo +F3 => F2 = --294.45 N Efx zo Joint ® Efx=0 » Fao ws38 = Fg eoszotto cosua → F10 = 340 N > F7 = f10 bin 30° — Fo sinago Ft = 170 N to the Fa sinago Ely co

3 Göy $ _ fa 1 Joint ® Efy zo > Fg sin 60 +Fq=0 => Fg = - 196. 30 N - Efx=o » F = F2 - Fg Cos 60° Fe = -19630 2 - Reaction calecelations- - Joint 6 :- Ery=o > R=0 Efe=o & Hp =FI 5 H, = = 196. 3 N Joint ☺ Efy=0 1. > R2 = - Fg sin6oo - fio Singoo - =) R2 5-170 N or R2 = 170 N(1) Efx=0 7 H2 = -fq CosGo - Fio Cos 30 => H₂ =-196.9 N or H2 = 196+3 N (es or HA = 196.3 N(*) IRY