Part A
An electron is moving east in a uniform electric field of 1.48 N/C directed to the west. At point A, the velocity of the electron is 4.47×105 m/s pointed toward the east. What is the speed of the electron when it reaches point B, which is a distance of 0.390 m east of point A?
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ve = | m/s |
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Part B
A proton is moving in the uniform electric field of part A. At point A, the velocity of the proton is 1.93×104 m/s , again pointed towards the east. What is the speed of the proton at point B?
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vp = | m/s |
Part A) ve = [ue2 + 2(eE/me)dAB]1/2
=> ve = {(4.47 * 105)2 + [2 * (1.6 * 10-19 * 1.48 * 0.39 / (9.1 * 10-31)]}1/2 = 6.35 * 105 m/s
Part B) vp = [up2 - 2(eE/mp)dAB]1/2
=> vp = {(1.93 * 104)2 - [2 * (1.6 * 10-19 * 1.48 * 0.39 / (1.67 * 10-27)]}1/2 = 1.62 * 104 m/s
Part A An electron is moving east in a uniform electric field of 1.48 N/C directed...
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