How many grams of NaOH (molar mass 40.0) are required to prepare 2.5L of 0.750 M solution?
Given the volume of NaOH solution, V = 2.5 L
Concentration of NaOH solution, M = 0.750 M = 0.750 mol/L
Hence moles of NaOH in the solution = MxV = 0.750 mol/L x 2.5 L = 1.875 mol
Given the molar mass of NaOH = 40.0 g/mol
Hence mass of NaOH required = 1.875 mol x 40.0 g/mol = 75.0 g (answer)
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