Question

Question 24 According to the following equation convert 16.0 grams of Co, to grams of CH4 CHA. 30, 200, + 2 H2O 1280 320 1440 18 05.09g 0.3649 O 1269 8.00 g 0.1829 U Question 25 According to the following equation convert of 6.21 grams of CH4 to grams of water. 2 CH4 + 19 0212 CO2 + 14 H2O 186 of [320) [440] [180] 1.30 g 9.109 43.59 0.1869 208 9 Question 26 A chemical reaction test

Answer 1

Question: 24

Mass of CO2 = 16 g

Molecular mass of CO2 = 44 gm/mol  

Moles of CO2 = mass / Molecular Mass = 16 / 44 = 0.3636 moles

C2H4 + 3O2 ==> 2CO2 + 2H2O

Strochiometrically ,

2 moles of CO2 produced from 1 moles of C2H4

0.3636 moles CO2 produced from 0.1818 moles of C2H4

Molecular mass of C2H4 = 28 g/mol

So mass of 0.18 moles = 0.18*28 = 5.09 g

So ,Option 'A' = 5.09 g is correct

Question: 25

Mass of C6H14 = 6.21gm

Molecular mass of C6H14 = 86 gm/mol  

Moles of C6H14 = mass / Molecular Mass = 6.21 / 86 = 0.0722 moles

2C6H14 + 19O2 ==> 12CO2 + 14H2O

2 moles of C6H14 form 14 moles of H2O

1 moles of C6H14 form 7 moles of H2O

0.0722 moles of C6H14 form 0.5054 moles of H2O

Molecular mass of H2O = 16 g/mol

So mass of the water form = 0.5054*18 = 9.0972 nearly equal to 9.10 g

So ,Option 'B' = 9.10 g is correct

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