9.15 cm below the center. If the target An archer lines up an arrow on the...

Question

Question

9.15 cm below the center. If the target An archer lines up an arrow on the horizontal exactly dead center on a target as draw

Answer 1

Answer #1

(1) In vertical, y = Vyst & 2 at ² 0-9.0915M = 0 + Ő (3-m/82) 22 [t = 0.1378 in horizonted, ax=0 Davot & Vo = 12 = 87080/8 0.

Answer 2

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