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Shown is the cross-section of a gravity retaining wall. Knowing that b = 14 ft and h = 28 ft, locate the center of gravity of
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u by I Area of ABCDEA, | h Ahh x 1/10 centroid of A = (xy) 23 10 10. A = Area of AGEE= - hxb = -bh 적응 하꽃 Az = Area of GHE= -v = ( bhs ) - ( ) (3 ) ( ) 이 - 밖 해 gg h -120931_t 1200- 1080

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