Question

In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). If the answer is zero enter "o". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p -value Treatments 1,200 C 20 600 Error Total 1,900 At a .05 level of significance, is there a significant difference between the treatments? The p-value is less thanol What is your conclusion? Cannot conclude that the means of the three treatments are equal o Hide Feedback Partially Correct Check My Work

Answer 1

Answer Date: 12/12/2019 The complete ANOVA table is, First, compute sum of squares, degree of freedom, mean square and F-statistics. The degree of freedom for between groups is, df BG=k-1 = 3-1 = 2 The degree of freedom error is, dfwg = N-k =(12+15+20)-3 = 44

The degree of freedom for total is, df total = N-1 = (12+15+20)-1 = 46 The sum of square error is, SS = SS Total – SS Treatmeni = 1900 - 1200 = 700 The mean square between groups is, MS 36 = SS 3G df BG 200 = 600

The mean square error is, MS: = de 700 44 =15.91 The F statistics is, Fob = Mosca 600 15.91 = 37.71 The F statistics is 37.71.

The p-value is, From F-ratio calculator, find p-value with the help of following steps: Enter F-ratio value Enter Degree of freedom Treatment and Degree of freedom Error. Press Calculate. The p-value is <.00001. The result is significant at p<.05. From F-ratio calculator, the p-value is 0. The complete ANOVA table is, | | F L 37.71 P 0 Source of Variation Treatment Error Total SS | df MS 1200 2 600 700 44 | 15.91 190046 ---- ---- ----