Q5 | Ans | Excel Formula |
1 | 0.9772 | =NORM.DIST(3,2,0.5,TRUE) |
2 | 0.3085 | =NORM.DIST(1.75,2,0.5,TRUE) |
3 | 0.6687 | =NORM.DIST(3,2,0.5,TRUE)-NORM.DIST(1.75,2,0.5,TRUE) |
Q6.
Here mu=15 and sigma =3
P(15<X<18)=P(mu<X<mu+sigma) = 34%
Ans: 34.13%
Question 5 1 pts Let X be normally distributed with meanu = 2.0 and 0 =0.5....
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