Question

Frequency of Cloud Cover over Minneapolis in January Time of day 1. 0 Fraction of sky covered 20.8 20.7 20.6 20.5 20.4 20.3 20.2 20.1 Midn. 3AM 6AM 9AM Noon 3.P. M 6P.M 9P.M 0.450.48 0.47 0.45 0.41 0.39 0.41 0.38 0.48 0.52 0.49 0.57 0.55 0.53 0.46 0.46 0.50 0.55 0.52 0.62 0.60 0.57 0.490.43 hos oss 0.52 0.56 0.54 0.64 0.63 0.59 0.52 0.47 0.54 0.59 0.57 0.66 0.65 0.61 0.54 0.49 0.55 0.59 0.59 0.69 0.67 0.64 0.55 0.51 0.56 0.59 0.62 0.72 0.68 0.66 0.58 0.56 0.58 0.62 0.64 0.74 0.71 0.69 0.60 0.60 0.60 0.67 0.66 0.78 0.74 0.71 0.62 0.62 0.66 0.71 0.72 0.89 0.86 0.84 0.79 0.66 (a) What percentage of time is at least half of the sky covered by clouds at 6 P.M.? 55 % (b) In order to model the frequency of an overcast sky as a function of the time of day, which variable must be held constant? . fraction of sky covered O time of day (c) Is the cross section in part (b) represented by a row or a column of the table? O row column (d) Find the function of the cubic cross-sectional model that gives the frequency of an overcast sky, where t is the number of hours after midnight, with data from Osts 21. (Convert the given frequency values to percentages. Then, use these percentages to find the function of the cubic model. Round all numerical values to three decimal places.) c(t, 1) = 5.05182 – 0.00212 +0.011t+ 0.455

Answer 1

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answer = 45.485 + 1.056*t -0.171*t^2 + 0.005*t^3