Question

Review The steel ingot has a mass of 2000 kg . It travels along the conveyor at a speed 0.6 m/s when it collides with the "nested" spring assembly. (Figure 1) Part A Figure ② 1 of 1 If the stiffness of the outer spring is ka = 5 kN/m, determine the required stiffness kb of the inner spring so that the motion of the ingot is stopped at the moment the front, C, of the ingot is 0.3 m from the wall. Express your answer to three significant figures and include the appropriate units. ? -0.5 m -- -0.45 m - Å Value R O a Units kp = KB KA Submit Request Answer Provide Feedback Next >

Answer 1

Conservation of mechanical energy Initial Ke of ingot = final spring potential enesgy » Homme = * Ka (0.5- 93)2 +(0.45-0.372 > 2000 X 0.62 = sovo x 0.2? + Ke x 0.152 1 kg = 2000 x0,62 - s000 x0.22 0.152 0. 31 K8 = 23.111.11 N/m, Tko = 23.111 kN/m. final position of mass