You have conducted a Chi-Square test for Homogeneity. Below are your results. LaTeX: \chi^2=2.987 χ 2...
You have conducted a Chi-Square test for Homogeneity. Below are your results.
LaTeX: \chi^2=2.987 χ 2 = 2.987
LaTeX: \alpha\:=\:0.01\: α = 0.01
critical value = 5.991
What is your decision?
Fail to reject Ho
Reject Ho
Not enough information
Homework Answers
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You have conducted a Chi-Square test for Homogeneity. Below are
your results.
LaTeX: \chi^2=2.987 χ 2...
If SPSS reports a "Sig." of 0.326 for a chi square and you are testing using...
If SPSS reports a "Sig." of 0.326 for a chi square and you are testing using an alpha level (α) of 0.01, the most appropriate decision would be to fail to reject the null hypothesis of your test. A. True B. False
A chi-square for goodness of fit hypothesis test was conducted using an alpha of .05. The...
A chi-square for goodness of fit hypothesis test was conducted using an alpha of .05. The resulting chi-square was as follows: X2(2, n = 30) = 4.20, p > .05. Find the critical value. What decision was made regarding the null hypothesis?
χ"crit-3.24 x-ob.-4.25 square oor. in robt 0.64 crit 0.68 d. Correlation: 23. Which option below contains...
χ"crit-3.24 x-ob.-4.25 square oor. in robt 0.64 crit 0.68 d. Correlation: 23. Which option below contains only things that match each other? a p<a, Obt in tail past Crit, Fail to Reject Ho b. p<a, Obt NOT in tail past Crit, Reject Ho c, p>α, Obt in tall past Crit, Reject Ho d, p>α, Obt NOT in tall past Crit, Fail to Reject Ho Which option below contains things that do not ALL match each other? a. p<α, test value...
Bassey Based on the following table, what would your decision be for this Chi-Square test with...
Bassey Based on the following table, what would your decision be for this Chi-Square test with an alpha of .05? fo fe fofe (fofe)2 4 (fofe)2/fe 0.4 8 10 -2 12 10 2 4 0.4 No Exercise Once a Week Twice a week More then Twice a week 16 6 36 10 10 3.6 3.6 4 -6 36 Chi- Square 8 F O reject the null hypothesis ye O none of the other answers o the results are inconclusive fail...
Consider a goodness-of-fit test with a computed value of chi-square - 1.273 and a critical value...
Consider a goodness-of-fit test with a computed value of chi-square - 1.273 and a critical value - 13.388, the appropriate conclusion would be to: reject Ho fail to reject Ho take a larger sample. take a smaller sample.
CHI SQUARE A die is tossed and the data appears below; 1. 6 5 4 3...
CHI SQUARE A die is tossed and the data appears below; 1. 6 5 4 3 1 Face 26 28 40 42 Freq Is this a fair die? Alpha=05 30 38 Н 5.Decision: (Circle one) Reject Ho or FTR Ho 1 Ho: 6. P-value 2 a 3 Critical Value 7.Statement: 4Test stat
Suppose you obtain a chi-square statistic of 67.81. Are your results statistically significant if the critical...
Suppose you obtain a chi-square statistic of 67.81. Are your results statistically significant if the critical value obtained from the distribution of chi-square is 3.84 with an alpha level of .05?
The frequency distribution shows the results of 200 test scores. Are the test scores normally distributed?...
The frequency distribution shows the results of 200 test scores.
Are the test scores normally distributed?
PART B. Determine the critical
value and the rejected region
PART C. Calculate the test statistic
PART D. Decide whether to reject or fail to reject the
null hypothesis
The frequency distribution shows the results of 200 test scores. Are the test scores normally distributed? Use α= 0.01. Complete parts (a) through (d) Class boundaries Frequency, f 49.5-58.5 20 58.5-67.5 62 67.5-76.5 79 76.5-85.5...
The frequency distribution shows the results of 200 test scores Are the test scores nomally distributed? Use α-0.10 Complete parts is) through (e) Class boundaries Frequency, 49.5-585 2D 58.5-67.5 51...
The frequency distribution shows the results of 200 test scores Are the test scores nomally distributed? Use α-0.10 Complete parts is) through (e) Class boundaries Frequency, 49.5-585 2D 58.5-67.5 51 67.5-76.5 B0 76.5-85.5 35 95.5-94.5 Using a chi-square goodness-of-fit test, you can decide, with some degree of certainty whether a variable is normally distributed. In all chi-square tests for nomality the null and alternative hypotheses are as follows Ho The test scores have a nomal distribution Ha The test scores...
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant...
Chi-Square Test for Independence Using Chi-Square, we are looking to see if there is a significant difference between what we would expect results to be, and what the actual results were. That is, expected vs. observed. Use alpha = .05 Listed below are data from a survey conducted recently where Males and Females responded to their happiness with their supervisor (this is fictitious data). Response Male Female Total Not at all 23 25 48 Somewhat 13 22 35 Very 26 16 42...
χ"crit-3.24 x-ob.-4.25 square oor. in robt 0.64 crit 0.68 d. Correlation: 23. Which option below contains only things that match each other? a p<a, Obt in tail past Crit, Fail to Reject Ho b. p<a, Obt NOT in tail past Crit, Reject Ho c, p>α, Obt in tall past Crit, Reject Ho d, p>α, Obt NOT in tall past Crit, Fail to Reject Ho Which option below contains things that do not ALL match each other? a. p<α, test value...
Bassey Based on the following table, what would your decision be for this Chi-Square test with an alpha of .05? fo fe fofe (fofe)2 4 (fofe)2/fe 0.4 8 10 -2 12 10 2 4 0.4 No Exercise Once a Week Twice a week More then Twice a week 16 6 36 10 10 3.6 3.6 4 -6 36 Chi- Square 8 F O reject the null hypothesis ye O none of the other answers o the results are inconclusive fail...
Consider a goodness-of-fit test with a computed value of chi-square - 1.273 and a critical value - 13.388, the appropriate conclusion would be to: reject Ho fail to reject Ho take a larger sample. take a smaller sample.
CHI SQUARE A die is tossed and the data appears below; 1. 6 5 4 3 1 Face 26 28 40 42 Freq Is this a fair die? Alpha=05 30 38 Н 5.Decision: (Circle one) Reject Ho or FTR Ho 1 Ho: 6. P-value 2 a 3 Critical Value 7.Statement: 4Test stat
The frequency distribution shows the results of 200 test scores.
Are the test scores normally distributed?
PART B. Determine the critical
value and the rejected region
PART C. Calculate the test statistic
PART D. Decide whether to reject or fail to reject the
null hypothesis
The frequency distribution shows the results of 200 test scores. Are the test scores normally distributed? Use α= 0.01. Complete parts (a) through (d) Class boundaries Frequency, f 49.5-58.5 20 58.5-67.5 62 67.5-76.5 79 76.5-85.5...
The frequency distribution shows the results of 200 test scores Are the test scores nomally distributed? Use α-0.10 Complete parts is) through (e) Class boundaries Frequency, 49.5-585 2D 58.5-67.5 51 67.5-76.5 B0 76.5-85.5 35 95.5-94.5 Using a chi-square goodness-of-fit test, you can decide, with some degree of certainty whether a variable is normally distributed. In all chi-square tests for nomality the null and alternative hypotheses are as follows Ho The test scores have a nomal distribution Ha The test scores...
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