Question

Solve the linear programming problem. (If there is no solution, enter NO SOLUTION.) Maximize Subject to X Y 156 Sy 5 220 The maximum value of 2 is Additional Materials Book Submit Answer Practice Another Version -/14.28 points TEAFM2 3.3.018. Solve the linear programming problem. (If there is no solution, enter NO SOLUTION.) Minimize X+Y Subject to 2x + y 2 27 *+ 2y 2 27 Minimum value is - Additional Materials eBook

Answer 1

max 2 = subject to 4nty ntys156 sury a 220 ya tad x,y), o sol we solve it by naya 156 graphical method when nzo y2156 10,156) 160,220) Shty=220 we have point 5C (0, 156), (156, og u Snth 2220 yzona 44 (Ag (1560 (44,0) rzo Y2220 (0,227 Now we find Az (0, 156) D. the point A B C B2 (0,211) nty/ 136 Sufyz 220 Zat A = Zat B axot xxot1562 156 470+ 111z 116. z ZatC = 4X21.87111 -n 2-64 na 16 y z 140 2 198.2. - (16,140) Zato z N 4x16+ 140 2 N 204 Inty 2 220 In 2 220-11 n 2 21.0 3 Max 2 = 204 B ( 7 (21.8, 11

mina a nty. Subject to auty >, 27 atzy 321 71217 y=17 Soll we solve it by graphical method.. lo ant (0,21 91 1 and find intersection A 79) B 709.97 X , 21 Zuty=27 nezy 227 Now we solne D and point (ù - 240 2dxyz 27 _22 +94 $4 - 3y - 27 y z g n zo e (2, (3,9 117,9 Az B 19,90 (175) 2 (17,171 =(5, 11) C x min 22 18 Zat A a 18 Zat B a 22 Zac 2 34 Zath & 22