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6. Suppose r0-0x8000, and the memory layout is as follows: Address Data 0x8007 0x8006 0x8005 0x8004 0x8003 0x8002 0x8001 0x8000 0x79 0xCD 0xA3 0xFD 0xOD 0xEB 0x2C 0x1A Suppose the system is set as little endian. What are the values of rl and r0 if the instructions are executed separately? (a) LDR (b) LDR (c) LDR (d) LDR rl, r1, r1, r1, [re] [r0, #41 [r0], #4 [r0, #41 ! r1 - r1 - r0 -Appendix 1: ASCII Table Char Dec Char Dec Char 60 61 ` &#97 ; &#98 0 0 NUL (null) 1 1 SOH (start of heading) 2 2 STX (Start of text) 3 3 ETX (End of text) 4 4 EOT (End of transmission 36 24 36 5 5 ENQ (Enquiry 6 6ACK (Acknowledge) 7 7 BEL (Bell》 32 20   64 40 &#64 ; 96 97 34 35 22 23 &#34 ; # 67 43#67 68 44 D 69 45#69 99 63 &#99 ; 10064 &#100: d 10165 &#101 ; e 10266 f f 103 67103 10468 &#104: h 105 69 105; i 1066A &#106: j 107 6B 107:k 1086C l 1 1096D m m 1106E n n 1116F o 11270 &#112, p 11371 q q 11472 &#114: r 115 73 115 S 11674 t t 11775 u u 11876 v V 11977 w w 12078 x 121 79 121 Y 1227A z z 1237B { { 1247C | 1257D } } 1267E ~ ~ 127 7F 127DEL 37 25 &#37 ; 39 27 ' 41 29 41 43 2B + 46 47 48 49 &#38 71 72 73 F &#71 ; H I 8 BS (Backspace) 9 9 TAB(Horizontal tab) 10 λ LF (HL line fa, new line) | 42 2A * 11 B VT (Vertical tab) 12 C FF (NP form fd, new page) | 44 2C &#44 ; 13 D CR (Carriage return) 14 ESO (Shift out) 15 F SI (Shift in) 16 10 DLE (Data link escape) 17 11 DC1 (Device control 1) 18 12 DC2 (Device control 2) 19 13 DC3 (Device control 3) 20 14 DC4 (Device control 4) 21 15 NAK (Negative acknowledge) 53 35 &53 22 16 SYN (Synchronous idle) 23 17 ETB (End of trans. block) 155 37 &#55 : 24 18 CAN (Cancel) 25 19 EM 《gnd of medium) 26 1A SUB (Substitute) 27 1B ESC (Escape) 28 1C FS (File separator) 29 1D GS (Group separator) 30 E RS (Record separator) 31 F US (Unit separator) 75 76 77 4B 4C 4D K L &#77: 45 2D - 46 2E . 47 2F 47 48 30 48 49 31 49: 5032 50: 51 33 &#51 ; 52 34 &#52: 79 80 4F 50 82 83 84 85 86 87 88 89 90 91 92 93 94 95 52 53 54 55 56 57 58 59 5A 5B O P &#81 ; R S &#84 ; U V &#87: &#88 ; Y Z & 91 ; 3 5 7 54 36 &#54 ; 56 38 8 57 39 57 58 ЗА : 59 3B &#59; 60 3C 60 61 3D &#61 ; 62 3E &#62 ; 63 3F ? 5c 92 5D ] 52 ^ 5FH95 ] www.bibase.comAppendix 2: Conditional Codes Unsigned BEQ BNE Compare Signed BEQ BNE BGT BHI BGE BHS BLO BLS BLT BLE

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6. Suppose r0-0x8000, and the memory layout is as follows: Address Data 0x8007 0x8006 0x8005 0x8004...
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