In Python 3 Write a LinkedList method named contains, that takes a value as a parameter and returns True if that value is in the linked list, but returns False otherwise.
Python method that you asked for:
def search(self, x):
current = self.head
while current != None:
if current.data == x:
return True #Return True if data is found
current = current.next
return False # Return False if data Not found
Full python program:
class Node:
def __init__(self, data):
self.data = data
self.next = None
class LinkedList:
def __init__(self):
self.head = None
def push(self, new_data):
new_node = Node(new_data)
new_node.next = self.head
self.head = new_node
def search(self, x):
current = self.head
while current != None:
if current.data == x:
return True #Return True if data is found
current = current.next
return False # Return False if data Not found
#Main method
linklist = LinkedList()
linklist.push(1);
linklist.push(2);
linklist.push(3);
linklist.push(4);
linklist.push(5);
if linklist.search(1):
print("True")
else:
print("False")
if linklist.search(6):
print("True")
else:
print("False")
Code screenshot:
Output:
In Python 3 Write a LinkedList method named contains, that takes a value as a parameter...
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