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Problem 1: Compute the maximum service axial compression load permitted on the built-up cross-section of the accompanying fig

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Giren, (K2)u= luft, (KL)x=42++ Steel section: 1992 กาสวยๆ Jก 9 = 18132 +2(33)]* (18-2) (32)3 12 - 12 . = 4561.6 in 4 similaFlexwral Buckling stress For = 10.658 se to (50/144.979) (50) = (0-658) = 43.2793 K31 Nominal compressive Strength Pn - For X

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