Question

question #3

ACANANGU Home - MyNCC Home Look Up Classes Located on Long Island, New York | NCC namumu www (Ha): e) In interval notation, state the conditions under which you FAIL TO REJECT THE NULL (Ho): f) Calculate the test statistic (to two decimals): g) Answer the question (yes or no): Are the means sales different than $150? QUESTION 3 Irene, an avid runner, has a previously known population mean u running pace of 6.15 mins/mile. Recently, she has been too busy to run regularly. On her 5 most recent runs she averaged a 6.38 mins/mile pace with a standard deviation 1 min/mile. At an alpha a 5%, is she really running slower as of late? (Note: "slower" means taking more time to complete the activity) {Please note la means "not equal" } a) State the null hypothesis (include the symbol (=, I=, >, <) and the value): Ho: b) State the alternative hypothesis (include the symbol (= I-, >, <) and the value): Ha: c) Find the critical z ort score(s) on the table: d) In interval notation, state the conditions under which you REJECT THE NULL (Ho) AND ACCEPT THE ALTERNATIVE (Ha): e) In interval notation, state the conditions under which you FAIL TO REJECT THE NULL (Ho): f) Calculate the test statistic (to two decimals): 9) Answer the question (yes or no): Is Irene really running at a slower rate? QUESTION 4 Suppose, according to a 1990 demographic report, the average U. S. household spends $90 per day. Suppose you recently took a random sample of 30 households in Huntsville and the results revealed a mean of $84.50 and standard deviation of $14.50. Using a 1% level of significance, can it be concluded that the average amount spent per day by U.S. households has decreased? {Please note != means "not equal" )

Answer 1

i He: Ho: 6.15 > 6.15 b u (if she is running late) For the with 4 a = 5% given example, we degrees of freedom. right failed ) is use t distribution Critical value at - teritorin 2.132 Accept if Reject the Null Hypothesis and the Alternative Hypothesis in interval Test Statistic € (teritical, ao ie Test Statistic & (2.132, o) we fail to reject the condition under which Null Hypothesis Test statistic € (-oo 2.132) Test statistic (under Mo). where s is - = X-1 Sla samiple standard 6.38-6.15 1/5 decration) = 0.51 rate No loune is not removing at a slower, since test statistic = 0.51 € (-0, 2.132), We do not have enough evidence to Reject the Null Hypothesis i.e. M = 6.15