Question

According to a recent report, the mean number of meals eaten at home is less than 700 per year. Suppose that a random sample of 100 households showed a sample mean number of meals prepared at home of 650. Assume the population standard deviation is 25. Test the claim that the population mean is less than 700 using a significance level of 0.05.

COPY AND PAST THE FOLLOWING INTO THE TEXT BOX BELOW AND THEN FILL IN YOUR ANSWERS using correct notation and vocabulary (type on the same line as the question - do not hit enter and then start typing):
You can also copy the following symbols to paste then where they are needed: \muμ,  \sigmaσ,  \alphaα,  \le≤,  \ge≥,  \ne​=
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• The Null Hypothesis: H_o :
  
• The Alternative Hypothesis: H_a:
  
• Which type of test will be used (left-, right-, two-tailed):
  
• \alphaα is:
  
• Describe the random variable:
  
• The distribution to use is:
  
• The test statistic is:
  
• The p-value is:
  
• Reject or Fail to Reject the Null Hypothesis, and why:
  
• State your conclusion about this test with a complete sentence:

Answer 1

> Test statistic: z = ă-M Tlto 650 -700 25/too - 20 p-value = Plza - 20) = Plz > 20) = 0 → p-value = 0 <0.0522 We will Reject to There is sufficient evidence to evidence to support the claim the population > that mean is less than 700