1. A fire insurance company thought that the mean distance from a home to the nearest fire department in a suburb of Chicago was at least 5.3 miles. It set its fire insurance rates accordingly. Members of the community set out to show that the mean distance was less than 5.3 miles. This, they thought, would convince the insurance company to lower its rates. They randomly indentified 57 homes and measured the distance to the nearest fire department from each. The resulting sample mean was 4.8 miles. If σ = 2.4 miles, does the sample show sufficient evidence to support the community's claim at the α = .05 level of significance?
(a) What is the appropriate alternate hypothesis?
Ha:μ ---Select--- > 4.8 >
5.3 < 5.3 < 4.8
(b) Find the p-value. (Give your answer correct to four
decimal places.)
(c) State the appropriate conclusion.
Reject the null hypothesis, there is not significant evidence that the mean distance is less than 5.3 miles.
Reject the null hypothesis, there is significant evidence that the mean distance is less than 5.3 miles.
Fail to reject the null hypothesis, there is significant evidence that the mean distance is less than 5.3 miles.
Fail to reject the null hypothesis, there is not significant evidence that the mean distance is less than 5.3 miles.
2.
While writing an article on the high cost of college education,
a reporter took a random sample of the cost of new textbooks for a
semester. The random variable x is the cost of one book.
Her sample data can be summarized by the following. The sample size
is 31; the sample mean is 119.31, and the sample standard deviation
is 17.97. (Give your answers correct to two decimal places.)
(a) Find the critical value for the sampling distribution for a 99%
confidence interval.
(b) Find the standard error for the sampling distribution for the
confidence interval.
(c) Find he margin of error for the confidence
interval.
(d) Find the 99% confidence interval to estimate the true mean
textbook cost for the semester based on this sample.
Lower Bound | $ |
Upper Bound | $ |
(e) The reason that a t-distribution is required for the sampling
distribution is:
Because the population mean is unknownBecause the population standard deviation in unknown Because the sample mean is unknownBecause the sample standard deviation is known
(f) Which of the following a correct description of the confidence
interval? (More than one may apply)
If we took 100 samples and constructed 100 confidence intervals, approximately 99 of them will contain the population mean
There is a 99% probability that the cost of a given text book is in the interval
We are 99% confident that the population mean is in the interval
99% of all the textbook costs are in the interval
1. A fire insurance company thought that the mean distance from a home to the nearest...
A fire insurance company thought that the mean distance from a home to the nearest fire department in a suburb of Chicago was at least 4.6 miles. It set its fire insurance rates accordingly. Members of the community set out to show that the mean distance was less than 4.6 miles. This, they thought, would convince the insurance company to lower its rates. They randomly indentified 61 homes and measured the distance to the nearest fire department from each. The...
A fire insurance company thought that the mean distance from a home to the nearest fire department in a suburb of Chicago was at least 4.5 miles. It set its fire insurance rates accordingly. Members of the community set out to show that the mean distance was less than 4.5 miles. This, they thought, would convince the insurance company to lower its rates. They randomly indentified 52 homes and measured the distance to the nearest fire department from each. The...
A fire insurance company thought that the mean distance from a home to the nearest fire department in a suburb of Chicago was at least 4.6 miles. It set its fire insurance rates accordingly. Members of the community set out to show that the mean distance was less than 4.6 miles. This, they thought, would convince the insurance company to lower its rates. They randomly indentified 61 homes and measured the distance to the nearest fire department from each. The...
A property and casualty insurance company (which provides fire coverage for dwellings) felt that the mean distance from a home to the nearest fire department in rural Alabama was at least 10 miles. It set its fire insurance rates accordingly. Members of the community set out to show that the mean distance was less than 10 miles due to the increased number of volunteer fire departments. This, they felt, would convince the insurance company to lower its rates. They randomly...
1. A(n) _____________ is the distance between a score and the mean of the group of scores. Variation ratio Standard deviation Dispersion Interquartile range Mean deviation score 2. The ___________ is a probability threshold or cutoff value used in hypothesis testing that signifies the level of risk we are willing to take in making a Type I error (i.e., false positive, or rejecting a true null hypothesis). binomial distribution conditional probability null hypothesis sampling distribution alpha level 3. Researchers commonly...
In a random sample of twelve people, the mean driving distance to work was 20.8 miles and the standard deviation was 5.4 miles. Assume the population is normally distributed and use thet-distribution to find the margin of error and construct a 99% confidence interval for the population mean mu. Interpret the results. Identify the margin of error.
1. The fuel economy information on a new SUV window sticker indicates that its new owner can expect 16 mpg (miles per gallon) in city driving and 20 mpg for highway driving and 18 mpg overall. Accurate gasoline records for one such vehicle were kept, and a random sample of mileage per tank of gasoline was collected. 19.0 16.6 19.9 22.8 18.7 18.2 18.0 15.4 19.1 20.5 16.9 20.4 21.6 18.6 20.8 16.5 16.9 16.9 17.9 16.9 19.9 16.1 17.6...
A random sample of 49 measurements from a population with population standard deviation o 3 had a sample mean of x, 9. An independeent random sample of sample mean of x, 11. Test the claim that the population means are 64 measurements from a second population with population standard deviation a2 4 had different. Use level of significance 0.01. (a) What distribution does the sample test statistic follow? Explain. The student's t. We assume that both population distributions are approximately...
In a sample of credit card holders the mean monthly value of credit card purchases was $ 400 and the sample variance was 67 ($ squared). Assume that the population distribution is normal. Answer the following, rounding your answers to two decimal places where appropriate. (a) Suppose the sample results were obtained from a random sample of 12 credit card holders. Find a 95% confidence interval for the mean monthly value of credit card purchases of all card holders. ( , )...
In a random sample of 11 people, the mean driving distance to work was 25.2 miles and the standard deviation was 7.3 miles. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Identify margin of error Construct a 95% confidence interval for the population mean (___,___)