Question

1. The fuel economy information on a new SUV window sticker indicates that its new owner can expect 16 mpg (miles per gallon) in city driving and 20 mpg for highway driving and 18 mpg overall. Accurate gasoline records for one such vehicle were kept, and a random sample of mileage per tank of gasoline was collected.

19.0	16.6	19.9	22.8	18.7	18.2	18.0	15.4	19.1	20.5
16.9	20.4	21.6	18.6	20.8	16.5	16.9	16.9	17.9	16.9
19.9	16.1	17.6	18.3	17.2	19.3	17.2	22.0	17.5	19.8
17.6	19.0	16.7	20.0	17.6	19.9	16.9	15.9	20.0	19.9
17.0	19.4	18.8	20.5	15.7	18.6	19.3	18.2	17.7	18.6

(a) Is an assumption of a normal sampling distribution reasonable?

No. The distribution of the sample is highly skewed, and n = 50 is not large enough.Yes. n = 50 is large enough.    No. The distribution of the sample is highly skewed, though n = 50 is large enough.No. The distribution of the sample is symmetrical, but n = 50 is not large enough.

(b) Construct a 95% confidence interval for the estimate of the mean mileage per gallon. (Give your answers correct to two decimal places.)
to  mpg

2. Complete the following hypothesis test: H_o: μ = 52, H_a: μ < 52, α = 0.01 using the data below. Assume the population is normal.

54

36

46

44

53

59

57

42

49

51

55

45

(a) The appropriate TI-83 Black Box Program for this problem is:

ZTestTTest    Chi-Square TestFTest

(b) Find the p-value. (Give your answer correct to four decimal places.)

(c) State the appropriate conclusion.

Reject the null hypothesis, there is not significant evidence that the mean is less than 52.Reject the null hypothesis, there is significant evidence that the mean is less than 52.    Fail to reject the null hypothesis, there is not significant evidence that the mean is less than 52.Fail to reject the null hypothesis, there is significant evidence that the mean is less than 52.

Answer 1

Please post remaining question separately , Thank you.

Mean 49.25 Variance 46.5682 n-1 Standard deviation 6.8241 v ariance a) sample size <30 and populatiOn sd notknown Student ttest will be used b) Test hypothesis are Hai μ <52 Test statistic t = 49.25-52 6.8241 /Vii2 t1.396 p-value -P(t<-1.396)-0.0951 c) Fail to reject the null hypothesis, there is not significant evidence that the mean is less than 52