Homework Answers
if a 224 virtual address space is mapped to 16 KiB (214bytes) pages, the number of virtual pages is 210 = (224 / 214)
= 1024 pages.
Since each entry into this page table has an address of size (24/8)3 bytes, then we have 2^10*3 = 3kB. So the page table takes up 3kB in memory.
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