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A 3.00- g sample of an alloy of Pb Lead was dissolved in nitric acid (HNO). Sulfuric acid was added to this solution, which p
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Answer #1

no of mol of PbSO4 precipitated = 1.69/303.26 = 0.0056 mol

no of mol of Pb present in sample = 0.0056 mol

mass of Pb present in sample = 0.0056*207.2 = 1.16 g

mass of Sn present in sample = 3.00 - 1.16 = 1.84 g

percentage of Sn in sample = 1.84/3*100 = 61.33%

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