Question

5: Homework 7 Remaining Time: 35:58:47 A pitot static probe is attached to the wing of an aeroplane flying at an altitude of 6.500 m. If the pressure difference measured by the probe is 663 kPa. determine the speed of the plane? Number Units

it doesnt suggest the density but onlnie its 0.5096

Answer 1

The density of air can be found from textbooks or online using the height given(6500 m).

density d = 0.62426 kg/m3 ( 0.5096 is the relative density. It should be multiplied with a reference density 1.225 kg/m3 )

Given Pressure difference  $\Delta P$ = 6.68 kPa

Therefore velocity   

P =0 dva

v =

2*6.68 + 103 T 0.62426

v = 146.292 m/s (Answer)