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Given the following function F(s) find f(t) F(8) = 8 +1 s(s+2)(+3) Show transcribed image text
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Identify f(t) for the function F(s) 8(+ 2)(8 + 3) s(s + 2)(s + 4) Multiple Choice (3.00+ 2.00e-2t-3.00e-4540 4.00u(t+ 2.00e-2t+3.00e-4t O (3.00 + 2.00e-2t +3.00e-44 3.00u(t) +2.00 e e-2t+4.00e-4 Find f(t) for the function F(s) = 32- 8s + 4 (s + 1)(8 + 2)2 Multiple Choice O 29=-24e-t+ (-12) -2t *+(-24)te-27 О = (13e-t +(-12)e-2t + (-24)te-21) (1) + O 10 = (13e-*+(-24)e-2 +(-12)te-210 80 = 8e-T+(-12)e-2t + (-24)te-2t Identify f(t) for the function F...
#6.) Given f(t)=-2:+8, Ost<4, f(t+4)= f(t). Find F(s)=L{f(t)} of the Periodic Function.
Find F(s). se{(7t + 1) U(t = 1)} F(S) = Submit Answer
s-3 12. Find the given inverse Laplace Transform. 2-1
8 7. (1 point) Find the inverse Laplace transform f(t) = C-' (F(s)) of the function F(s) = $-2 10=c='{, *2 -3} - help (formulas)
(1 point) Find the inverse Laplace transform f(t) = 2" (F(s)} of the function F(s) = 2s 8²-1 (t) = -1 ^{}--G-- help (formulas)
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Find f(t) for the function F(s) = 52 - 8s + 4 (s + 1)(8 + 2)2 Multiple Choice O =-24e-t+ + (-12)e-2t+6 +(-24)te-27 O 19 = (13e-++(-12)e-2t +(-24)te-210 O p0 = (13e-+ +(-24)e-2t+ (-12)te-24) (0) O 10 = 8e-t +(-12)e-2t *+ (-24)te-27 Identify f(t) for the function F (s) = 32 + 1 (s+3)(s2+4s+5) Multiple Choice 5e-3t_4e-2 tsin(t) О (5e-3t_4e-2tcos(f)( (5e-3t+4e-2tcos() 4e-36-5e-2tcos()
The Laplace transform of the piecewise continuous function $4, 0<t<3 f(t) is given by 2, t> 3 1 L{f} (1 – 2e-st), 8 >0. S None of them L{f} = (1 – 3e®), s>0. 2 L{f} (3 - e-), 8 >0. S 2 L{f} (2-est), s >0. S
The Laplace transform of the piecewise continuous function $4, 0<t<3 f(t) is given by 2, t> 3 1 L{f} (1 – 2e-st), 8 >0. S None of them L{f} = (1 – 3e®), s>0. 2 L{f} (3 - e-), 8 >0. S 2 L{f} (2-est), s >0. S
a each function. 2. Find the aamam a. -2 For the given Puuction f,Eind t-3) -) Fl-1), urd 4(0). 3 1 -2ズ+3
a each function. 2. Find the aamam a. -2 For the given Puuction f,Eind t-3) -) Fl-1), urd 4(0). 3 1 -2ズ+3