Question

please explain your answer as i am a little slow

For the following questions, provide the following information, (1) If a molecular formula is provided, indicate the units of unsaturation in this molecule. (2) Label any important relevant peaks in the IR spectrum by indicating which type of bond it corresponds to (3) If the integration is not provided in the 'H NMR spectrum, determine the integration for each signal in this spectrum (4) Examine the mass spectrum carefully. If I have placed an asterisk above a peak, propose a valid structure for this ion. (5) Label the 'H NMR and ''C NMR according to what type of H or C it corresponds to. (6) Finally, propose a structure for the molecule corresponding to the spectra information provided for each of these questions. Show all of your work for partial credit. The correct structural assignment is worth 1 to 1.5 pts, while (1) through (5) is worth 1.5 to 2 points. Question number 10 is an unknown which I will give you. When I give you this sample, along with its molecular formula, you will obtain an IR, a 'H NMR, and a '°C spectrum for this sample. With this data, you will provide the following: 1. Units of unsaturation. (Show your work for partial credit.) 2. Label all relevant peaks in the IR. 3. Label all possible peaks in the 'H NMR spectrum. 4. Label all possible peaks in the '°C NMR spectrum. 5. Provide the identity of this compound. Feel free to use additional sheets of paper while working through this handout and turn these in (in an organized and legible form) to show your work for partial credit.

Answer 1

Answer] » IR Spectrum Data 1725 cho → ester carbonyl group is present (Réer') 1200 na! > --o- bood of ester y m/2=74, indicate that Mass spectrum bata 1)/2= 74cm+), G5, 31, 29 = The mass of molecular iom at m/2=74, ind molecular weight of compound is 74. – molecular loomula - Rule ok 13 ( 74 ) => n= 5 and 7= 9 cular iom at In Hn to= C5H14 But Compound have to two exygen atom. Then remove C2H8 from the Iormula of ruleos 13. Then moleculat borrowla of Compound is CzHCOZ => Deqoee sob unsakerrabiom= 24+2+H = 2x3+2-6 Compound hove one degree of unsaturabicos. This is ester Carbonyl grcrep. 3) 13C-NMR Data Protes decorupled,- 23,60, 161, ppm. Proken corepled=5 23 ppm (9) Chlz- Goppro ()3-10 161ppm (d) -TH

4) IH NMR data 1.5(t, 3H) = (C17che 4.219, 2H) = fcho- 8.0(5, 1H) 3 -&H 23 66 0 161 Structure o's Compound - t t Chh (850-c-148.0(s) - 4.2(9) ST (t) Mass Fragmentations m12-29 Holy teo T er] > D. ŠH mclabberty the ] , obou M12=45 m/2=46