Question

Problem 12 Constants Part A A0.360-m-long cylindrical capacitor consists of a solid conducting core with a radius of 1.20 mm and an outer hollow conducting tube with an inner radius of 2.05 mm. The two conductors are separated by air and charged to a potential difference of 6.30 V Calculate the charge per length for the capacitor νο ΑΦ C/m Submit Request Answer Part B Calculate the total charge on the capacitor Vο ΑΣφ

Answer 1

Part-C

Capacitance of cylindrical capacitor is given by,

C = 2*pi*$\epsilon$o*L/ln(b/a)

given, L = length of capacitor = 0.360 m

b = outer radius = 2.05 mm

a = inner radius = 1.20 mm

$\epsilon$o = 8.85*10^-12

So, C = (2*pi*8.85*10^-12)*0.360/ln(2.05/1.20)

C = 3.74*10^-11 F

Part-B

Since, Q = C*V

given , V = Potential difference = 6.30 V

So, Q = (3.74*10^-11)*6.30

Q = 2.36*10^-10 C

Part-A

Charge per length for capacitor will be:

$\lambda$ = Q/L

$\lambda$ = (2.36*10^-10)/0.360

$\lambda$ = 6.56*10^-10 C/m

Part-D

Energy stored in capacitor is given by,

U = 0.5*C*V^2

U = 0.5*(3.74*10^-11)*6.30^2

U = 7.42*10^-10 J